In this case, the truth values for ~(p∧q) and ~p∨~q are exactly the same, so we can conclude that the two statements are equivalent ~(p∧q)≡~p∨~qSo, if we ever encounter ~(p∧q), we can replace it with ~p∨~q without changing the logical meaning of the statement!Now let's try comparing two more complex statements to see if they are equivalentDoes the conclusion must be true?

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If p then q q therefore p example
If p then q q therefore p example-P q p → q ∼ q ∼ p T T T F F T F F T F F T T F T → F F T T T In this case there is only one critical row to consider, and its truth value it true Hence this is a valid argument Result 22 (Generalization) Suppose p and q are statement forms Then the following arguments (called generalization) are valid p p∨q q p∨ q Result 23And if p then r;




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Addition If P is a premise, we can use Addition rule to derive $ P \lor Q $ $$\begin{matrix} P \\ \hline \therefore P \lor Q \end{matrix}$$ ExampleTherefore p is true Conjunction p,q ∴ (p∧q) p and q are true separately;For example, if the claims P and Q express the same proposition, then the argument would be trivially valid, as it would beg the question In everyday discourse, however, such cases are rare, typically only occurring when the "ifthen" premise is actually an " if and only if " claim (ie, a biconditional / equality )
To say that q is a "necessary component" of p is to mean that if one has p one must also have q, that is "if p then q" For example, "an engine is a necessary component of a functioning automobile" means that if one has a functioning car then one has an engine, rather than if one has an engine then one has a functioning car So, Morris' argument is as follows If you believe inAs far as I understand, If p then Q means " if P is true, Q has to be true Any other case, I don't know " So, from what I understand, the first 2 rows of the truth table state that " If P is true and Q is true, the outcome is correct and If P is true and Q is false,P ^ q is trueif and only if p and q are both true Example Alice is tall AND slim Truth table for conjunction p q p ^ q T T T T F F F T F F F F c Xin He (University at Buffalo) CSE 191 Discrete Structures 11 / 37 Disjunction Another binary operator isdisjunction _ , which corresponds toor, (but is slightly different from common use)
上 if p then q if q then r therefore if p then r If p then q or r ;False The key to identifying an argument in context is to first identify the conclusion, then look for the premises a True b False This classic argument "The Bible says that God exists;Is P and Q 2 is P and Q a n is P and Q Conclusion (generalization) All Ps are Qs An argument is strong if and only if the premises provide significant support for the conclusion That is, if the premises were true, then it is likely that the conclusion is true Another way of putting this is that the truth of the premises




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Therefore they are true conjointly Addition p ∴ (p∨q) p is true;Example If we turn of the water in the shower, then the water will stop pouring If we call the first part p and the second part q then we know that p results in q This means that if p is true then q will also be true This is called the law of detachment and is noted $$\leftIt consists of the antecedent (the part introduced by the word if) and the consequent (the part introduced by the word then) Consequent The part of a conditional statement (If p, then q) introduced by the word then Deductive Argument




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The final (or concluding) statement in an argument Symbol for "therefore", normally used to identify the conclusion of an argument Latin for "method of affirming" A rule of inference used to draw logical conclusions, which states that if p is true, and if p implies q ( pq ), then q is trueIf I have a college degree, then I am not lazy (p →~ q) I don't have a college degree )(~ p Therefore, I am lazy q Hypothesis )((p →~ q)∧~ p Conclusion q Argument in symbolic form (( p →~ q)∧~ p) →q To test to see if the argument is valid, we take the argument in symbolic form and construct a truth tableIf p→q is a conditional statement, then (1) q→p is called converse of p→q (2) ¬q→¬p is called contrapositive of (3) ¬p→¬q is called inverse of p→q EXAMPLE p Ram is a computer science student q Ram study DBMS p→q If Ram is a computer science student, then the will study DBMS




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One way to write the conditional is "if p, then q" Thus, if you know p, then the logical conclusion is q Consider this as you review the following truth table Why is this true?(pVq) V (~p^q) → q p q ~p p V q ~p ^ q (p V q) V (~p ^ q) (p V q) V (~p ^ q) → q T T F T F T T T F F T F T F F T T T T T T F F T F F F T Problem 18 (15 points) Write each of the following three statements in the symbolic form and determine which pairs are logically equivalent a6 CHAPTER 1 LOGIC 14 Converse and Contrapositive The converse of the implication p!qis q!p The example above shows that an implication and its converse can have di erent truth values, and




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Solution In Example 1, the sentence, "I do my homework" is the hypothesis and the sentence, "I get my allowance" is the conclusion Thus, the conditional p q represents the hypothetical proposition, "If I do my homework, then I get an allowance" However, as you can see from the truth table above, doing your homework does not guarantee that you will get an allowance!If p then q;Therefore either not p or not r Simplišcation (p∧q) ∴ p p and q are true;




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The argument is valid modus ponens inference rule We cannot conclude that the conclusion is true, since one of its premises, p 2 > 3 2, is false Indeed, in this case the conclusion is Conditional statement if she studies math (p), then she will find a good job (q) This is of the type If p, then q q unless p She finds a good job unless she does not study math Here q is true only is ~p (not p) is false If ~p is true then q will become false Hope this helped!Therefore, God exists" is an example of begging the question a True




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Therefore if p is trueWays in which the propositions may fail to be equivalent Here is another example Example 232 Show (p!q) is equivalent to p^q Solution 1 Build a truth table containing each of the statements p q q p!q (p!q) p^q T T F T F F T F T F T T F T F T F F F F T T F F Since the truth values for (p!q) and p^qare exactly the same for all possible5月 30, 21 Result 26 (Transitivity) Suppose p, q and r are statement forms Then the following argument (called transitivity) is valid p → q q → r p → r Result 27 (Proof by Division into Cases) Suppose p, q and r are




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P then q" or "p implies q", represented "p → q" is called a conditional proposition For instance "if John is from Chicago then John is from Illinois" The proposition p is called hypothesis or antecedent, and the proposition q is the conclusion or consequent Note that p → q is true always except when p is true and q is falseTherefore, the argument must be valid 5 Valid We can test for validity by substituting statement variables into the argument If we do the substitution, we get If p, then q Not q Therefore, not p Upon inspection, we find that this is one of the common patterns of valid inference discussed above—modus tollensGiven "p implies q", there are two possibilities We could have "p", and therefore "q" (so q is possibility 1)



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Specifically given two propositions p and q, then the resulting proposition 'p or q' means 'p or q' is a true proposition even when both p and q are true An example would be, "John is a student or John is a father' If John is both a student and a father, then the entire sentence is still true The phrase 'exclusive or' means 'p or q but notFor example, in terms of propositional logic, the claims, "if the moon is made of cheese then basketballs are round," and "if spiders have eight legs then Sam walks with a limp" are exactly the same They are both implications statements of the form, P → Q P → Q 🔗NotQ 3 Therefore, Q 3 Therefore, P Two Common Invalid Argument Forms Affirming the Consequent 1 If P, then Q 2 Q 3 Therefore, P Denying the Antecedent 1 If P, then Q 2 notP 3 Therefore, notQ




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So, in the Form given above, the consequent is "q" For example, in the statement "if today is Tuesday, then I have logic class", "I have logic class" is the consequent To affirm the consequent is, of course, to claim that the consequent is true Thus, affirming the consequent in the example would be to claim that I have logic classIf I use my turning signal while driving in MO then I will go to jail Disjunctive Syllogism Form p or q not p therefore q Disjunctive Syllogism ( valid and sound) I will eat either yogurt and granola or a bagel and cream cheese for breakfast tomorrowP is called the hypothesis and q is called the conclusion For instance, consider the two following statements If Sally passes the exam, then she will get the job If 144 is divisible by 12, 144 is divisible by 3



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The Converse of a Conditional Statement For a given the conditional statement {\color{blue}p} \to {\color{red}q}, we can write the converse statement by interchanging or swapping the roles of the hypothesis and conclusion of the original conditional statement Therefore, the converse is the implication {\color{red}q} \to {\color{blue}p} Notice, the hypothesis \large{\color{blue}p} of theBut either not q or not s;In conditional statements, "If p then q" is denoted symbolically by "p q";




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Answer (1 of 6) The easiest way is by recalling that the contrapositive has the same truth value as the original statement So since P implies Q is true then not Q implies not P is also true However, the question remains how do we know that the contrapositive is true given the statement is truIs true if either P is true or Q is true (or both remember that we're using "or" in the inclusive sense) It's only false if both P and Q are false Here's the table for logical implication To understand why this table is the way it is, consider the following example "If you get an A, then I'll give you a dollar"2 then (p 2)2 > (3 2) 2 We know that p 2 > 3 2 Therefore, (p 2)2 = 2 > (3 2) 2 = 9 4 Is the argument valid?



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Solution We want to use the p and q given above as replacements for the p and q in the following argument form (such use is called a replacement instance) If p then q not q Therefore not p Hence we have for (a) If my car is still in the shop then I have to get a ride with a friend I don't have to get a ride with a friend If p, then q Not q Therefore, not p If you don't care, fuck off The Rubber Duck method of debugging We called it the Rubber Duck method of debugging It goes like this 1) Beg, borrow, steal, buy, fabricate or otherwise obtain a rubber duck (bathtub variety) 2) Place rubber duck on desk and inform it you are just going to go over someA conditional statement is a statement of the form "If p, then q" The symbol for this "ifthen" connective is the arrow → That is, the statement "if p, then q" is denoted p→q EXAMPLE 221 Let p represent "You drink Pepsi" Let q represent "You are happy" In this case p→q is the statement "If you drink Pepsi, then you are happy"




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The Bible is true because God wrote it;Rule of inference Modus tollens Definition It has the form If p, then q ∼ q ∴ ∼ p The term modus tollens in Latin means "method of denying" p q p → q ∼ q ∼ p T T T F T F F T F T T F F F T T T Example If Zeus is human, then Zeus is mortal Zeus is not mortal ∴ Zeus is not humanAnd if r then s;



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–premises p 1, p 2, , p k –conclusion q then (p 1Ùp 2Ù Ùp k) ®q is a tautology •Ex ( (p®q)Ùp ) ®q is a tautology •Some simple valid argument forms, called rules of inference, are derived and can be used to construct complicated argument formP q r q p r ∴ q aka Disjunction Elimination Corresponding Tautology ((p q) ∧ (r q) ∧ (p r )) q Example Let p be "I will study discrete math" Let q be "I will study Computer Science" Let r be "I will study databases" "If I will study discrete math, then I will study Computer Science"P → q = (~p ∨ q) In the Principia Mathematica, the "=" denotes "is defined to mean" Using this denotation, the above expression can be read "p implies q is defined to mean that either p is false or q is true" The following truth table shows the logical equivalence of "If p




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For example there is no necessary connection between P='22=4' and Q='Washington is the capital of USA',still the inference P > Q is valid,that is always a TRUE implies a TRUE irrespective of the relations between the terms of the propositions P and Q in the russelian (material) definitionOn the other hand there is a necessary one between PTherefore the disjunction (p or q) is true Composition (p → q) (p → r) ∴ (p → (q∧r)) if p then q;




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